Question

For an isolated parallel plate capacitor of capacitance C and potential

difference V, what will be the change in (i) charge on plates (ii) potential

difference across the plates (iii) electric field between the plates (iv) energy

stored in the capacitor, when the distance between the plates is increased ?​

Answer 1

Answer:

hi

Explanation:

The charge Q on the plates is proportional to the potential difference V across the two plates. The capacitance C is the proportional constant, Q = CV, C = Q/V. C = ε0A/d.