Question

for an isolated system ∆u=0 , what will be ∆s?​

Answer 1

Answer:

Δs > 0

Explanation:

Δ S = p∆V /T

T Δ S = p Δ V

p Δ V > 0

So ∆s > 0

Answer 2

Answer:

Δs > 0

Explanation:

Consider two bubs each having gas connected by a stop clock and isolated from the surrounding as an example of an isolated system.On opening the stop clock, the 2 gases mix up.

As a result, more space is available for each gas to move apart i.e. system becomes more disordered. This shows that Δs > 0 i.e. Δs is positive.

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