Question

for an isosceles triangle ABC right angled at A, find sinB cosC+sinC cosB​

Answer 1

Step-by-step explanation:

sinbcosc + sinccosb = 2x^2/Y^2 = 2

Answer 2

Answer: 1

Step-by-step explanation:ABC is an issolese right angle triangle at A

So ,side c =side b=x

So it's remaining two angles are of 45°

Sin c . Cos b + cos c. Sin b = sin (c+b)

Sin (a+b)=sin90°

So

Sin(c+b)=1

Sin b. Cos b +cos b.sin c =1