Question

For an isothermal expansion of a perfect gas, the value of $\frac{\triangle P}{P}$ is equal to
(a) $-\gamma^{1/2}\frac{\triangle V}{V}$
(b) $-\frac{\triangle V}{V}$
(c) $-\gamma\frac{\triangle V}{V}$
(d) $-\gamma^{2}\frac{\triangle V}{V}$

Answer 1

The answer of u r question

Option.C

Answer 2

Answer:

Explanation:

☢️PLEASE MARK AS BRAINLIEST☢️