Question

For an object moving with an initial speed of 72 km/hr, what is the time required to stop it with a deceleration of 2m/s^2​

Answer 1

Answer :-

Given :-

• Initial velocity = 72 km/h = 72 × 5/18 = 20 m/s
• Final velocity = 0
• Acceleration = - 2 m/s²

To Find :-

• Time

Solution :-

We know that,

→ v = u + at

where

• v is final velocity
• u is initial velocity
• a is acceleration
• t is time taken

Here, we are given final velocity, initial velocity and acceleration. So, by simply substituting the value in formula, we can find time :-

→ 0 = 20 - 2 × t

→ 2t = 20

→ t = 20 / 2

→ t = 10

Time = 10 seconds