For an object of mass ( m ) falling free from rest at a height h . The linear momentum of this object before reaching the ground is
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v^2 -vo^2 = 2 γ y => ( consevation of energy)
vo=0 and v= 3/2 g h ^1/2 => v^2 = 2γ y + work ( air drag ) ; where y=h ; and γ = g ( gravity) .=>
w = 9/4 g^2 h -2gh = h g( ( 9/4)* g-2)
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the linear momentum of this object before reaching the ground is kinetic energy.
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almahahamads:
Ok but why can you give more details
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