Physics, asked by manojreddy7377, 2 months ago

For an object of mass 'm', falling freely from height 'h', under acceleration due to gravity 'g', If v is the velocity of the object at a given instant, then during the course of its fall, for all points, which of the expression given below is correct ? *
1 point
mgh > 1/2 mv2
mgh < 1/2 mv2
mgh = 1/2 mv2
mgh + 1/2 mv2 = Constant​

Answers

Answered by amalroshan18
3

Answer:

mgh+1/2mv2=constant

Explanation:

As gravity is a conservative force the total energy of the system always remans constant

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