For an object projected from ground range is two times and maximum height attained by it the horizontal range of object is
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Hey ....
We know that
R/H= 4/(tanA). (Let A as the angle of projectile)
Now
R=2H (Given)
So
2H/H= 4/tanA
1/2=tanA
A = 45°
using formula of range
R=(u²sin90°)/g
R=u²/g
We know that
R/H= 4/(tanA). (Let A as the angle of projectile)
Now
R=2H (Given)
So
2H/H= 4/tanA
1/2=tanA
A = 45°
using formula of range
R=(u²sin90°)/g
R=u²/g
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