Question

For an object projected from ground with speed u horizontal range is two times the maximum height attained by it.The horizontal range of object is

Answer 1

ʟᴇᴛ θ ʙᴇ ᴛʜᴇ ᴀɴɢʟᴇ ᴏғ ᴏʙᴊᴇᴄᴛ ғʀᴏᴍ ɢʀᴏᴜɴᴅ.
ɢɪᴠᴇɴ,
ʜᴏʀɪᴢᴏɴᴛᴀʟ ʀᴀɴɢᴇ = 2 × ᴍᴀxɪᴍᴜᴍ ʜᴇɪɢʜᴛ
        ᴜ2sɪɴ2θɢ = 2×ᴜ2sɪɴ2θ2ɢ 2 sɪɴθ ᴄᴏsθ = sɪɴ2θ               ᴛᴀɴθ = 2 sᴏ,       ᴄᴏsθ = 15√                sɪɴθ = 25√ ᴛʜᴇʀᴇғᴏʀᴇ,ʜᴏʀɪᴢᴏɴᴛᴀʟ ʀᴀɴɢᴇ,                        = ᴜ2sɪɴ2θɢ                        = 2ᴜ2 sɪɴθ ᴄᴏsθɢ                        = 45ᴜ2ɢ           

Answer 2

HEYY

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