Question

For an opaque plane surface the irradiation, radiosity and emissive power are respectively 20, 12 and 10 w/m2. The emissivity of the surface is

Answer 1

The emissivity of the surface is 0.8

Explanation:

This problem can be solved by using the following formula and method.

Given data:

Radiosity "J = 12 w/m^2

Irridation = 20 w/m^2

Emissive power = 10 w/m^2

J = ε Eb  + ( 1 - ε)G

12 = ε x 10 + ( 1 - ε) x 20

12 = ε10 + 20 - 20ε

20ε - 10ε =  20 -12

10ε = 8

ε = 8/10

ε = 0.8

Thus the emissivity of the surface is 0.8

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