Question

for angle of banking more than 45degree whatbis the value of maximum speed ​

Answer 1

Answer:

172 m/s

Explanation:

Given that: r=1000m,θ=45

0

,μ=0.5,m=2000kg

We know that maximum safe velocity for a banked is given by :

v=

1−μtanθ

rg(tanθ+μ)

hence on putting the given values, we get

v=

1−0.5tan45

1000×9.8×(tan45+0.5)

or v=172m/s

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