Question

for any acute angle of Q the value of 1+tan²Q is​

Answer 1

Answer:

so your ans is $sec^{2} Q$

Step-by-step explanation:

we know that $sec^{2}x - tan^{2}x$ = 1

             so,      $sec^{2}Q = 1 + tan^{2}Q$

so your ans is $sec^{2} Q$