For any angle theta!, state the value of:-
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For any angle Θ , sin²Θ + cos²Θ = 1.
Proof : Let in triangle ABC , angle c = Θ.
SinΘ = Side opposite to Θ / Hypotenuse = AB / AC.
CosΘ = Adjacent side to Θ / Hypotenuse = BC / AC
We have , AB² + BC² = AC².
Now ,
= Sin²Θ + Cos²Θ
= ( AB / AC )² + ( BC / AC )²
= AB² / AC² + BC² / AC²
= ( AB² + BC² ) / AC²
= AC² / AC²
= 1.
Proof : Let in triangle ABC , angle c = Θ.
SinΘ = Side opposite to Θ / Hypotenuse = AB / AC.
CosΘ = Adjacent side to Θ / Hypotenuse = BC / AC
We have , AB² + BC² = AC².
Now ,
= Sin²Θ + Cos²Θ
= ( AB / AC )² + ( BC / AC )²
= AB² / AC² + BC² / AC²
= ( AB² + BC² ) / AC²
= AC² / AC²
= 1.
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naveekutty2:
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