Question

For any base a, (a > 0, a +1), prove that
1
In each of the following assumethat the base​

Answer 1

Step-by-step explanation:

Base case : a^0=1 is true by definition.

Inductive case : assume a^m =1 for all m such that 0<=m <=k.

We must then use the assumption to show a ^(k+1)=1.

Observe that a^(k+1)=(a^k)(a^k)/(a^(k-1)).