Math, asked by vanshchoudhary76, 5 months ago

For any base a, (a>0,a≠1),prove that:log a^(mnp)=log a^m +log a^n+log a^p.​

Answers

Answered by nandellamayank
4

Step-by-step explanation:

prove this:║ log ₐ^m + log ₐ^n + log ₐ^p = log ₐ^mnp ║

log ₐ^m + log ₐ^n + log ₐ^p = 1/mlog ₐ + 1/nlog ₐ + 1/plog ₐ

1/mlog ₐ + 1/nlog ₐ + 1/plog ₐ = 1/mnplog ₐ

1/mnplog ₐ = log ₐ^mnp

∴ therefore, LHS = RHS, Hence proved

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