Question

For any base show that
log (I+ 2+ 3) = log I+log 2 + log 3​

Answer 1

Answer:

log(1+2+3)=log1+log2+log3

we know that,

logm+logn=log(m+n)

therefore,

log(1+2+3)= log(1+2)+log3

again,

log(1+2+3)=log(1+2+3)

on equating we get,

( 1+2+3)=(1+2+3)

6=6

=0

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