For any integer a show that (2a+1,9a+4)=1
Answers
Answered by
1
Answer:
Let
d=gcd(2a+1,9a+4)
Then
d|2a+1
and
d|9a+4
2a+1=db
and
9a+4=dc
a=db−12
and
a=dc−49
Equating both equations :
9db−9=2dc−8
d(9b−2c)=1
9b−2c=1d
Now, since b and c are integers, therefore 1d is an integer, i.e d divides 1 and therefore
gcd(a,b)=d=1
.
Similar questions