Question

For any integer p, P+1=-_____where as p +0is______​

Answer 1

Answer:

$\huge\boxed{\tt\purple{Answer}}$

Step-by-step explanation:

Every odd number can be written in the form of 4k+1 or 4k+3 where k is an integer.

Case i) p=4k+1

Then p2−1=16k2+8k=8(2k2+k)

We see that p2−1 is divisible by 8 and hence also by 4.

Case ii) p=4k+3

Then p2−1=16k2+24k+8=8(2k2+3k+1)

We see that p2−1 is divisible by 8 and hence also by 4.

So in both the cases p2−1 is divisible by 8