For any natural number n, 7^n – 2^n is divisible by 5.
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proud the following statement by mathematical induction.
7n-2n is divided by 5 for eachinteger n>1
my Airtel let the given statement be p(n)
(1)7-2= why is divisible by 5 so p(k)is true .
suppose and as an inductive Hypothesis, 7k-2k is divisible by 5 for each integer k>1 that is p(k) is true:
7k+1-2k+=7k1-(7-5)k+1
I am stuck on this time I think I have to straight a multiple of 5 from the above equation but I can't
7n-2n is divided by 5 for eachinteger n>1
my Airtel let the given statement be p(n)
(1)7-2= why is divisible by 5 so p(k)is true .
suppose and as an inductive Hypothesis, 7k-2k is divisible by 5 for each integer k>1 that is p(k) is true:
7k+1-2k+=7k1-(7-5)k+1
I am stuck on this time I think I have to straight a multiple of 5 from the above equation but I can't
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