Question

For any natural number n >1 even or odd, write the general form of a Pythagorean Triplet

Answer 1

Step-by-step explanation:

Given For any natural number n >1 even or odd, write the general form of a Pythagorean Triplet

• So to find the Pythagorean triplet we have
• The lengths of the side of a right angle satisfy the theorem of Pythagoras then these
• numbers are known as Pythagorean triplets.
• So we have a^2 + b^2 = c^2
• So the hypotenuse is the longest side of the triangle that is c and a and b are the other two sides.
• A few examples are 3,4,5 = 3^2 + 4^2 = 5^2
• Also 9,40,41 = 9^2 + 40^2 = 41^2
• A Pythagorean triplet always has all even or two odd and an even number.
• So for forming this triplet we have when p and q are positive integers p > q we get
• So a = p^2 – q^2
• So b = 2pq and
• So c = p^2 + q^2

Reference link will be

https://brainly.in/question/1207925