Question

For any natural number n show that 2^n+ (-1)^n+1 is divisible by 3​

Answer 1

Answer:

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Step-by-step explanation:

So we get 2n+1+1,→2n+2+1,→3k+3=3(k+1). Thus 2n+1 is divisible by 3. ... n=1, then 2+1=3, and 3|3. Let n=2k+1, since n is odd, then we get 22k+1+1=3m.