For any particle if the displacemant in 1/4th of the time period is 0.3m, then what is the radius of circle?
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Answer:
0.21
Explanation:
T/4 ==> 0.3 m which gives right angled triangle
By pythegorous theorem,
0.3^2 = 2 a^2
√0.09 /2 = a
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