Question

for any poison variate x, if p(2)=p(3), then prove that p(4)=16e^-3

Answer 1

Value of p= -5
given equation=x^3+15px+p^3-125=0
putting value of p in given equation
x^3+15(-5)x+(-5)^3-125=0
x^3-75x+125-125=0
x^3-75x=0
x(x^2-75)=0
x=0         X^2-75=0
               X^2=75
               X=root 75
               X=5 root 3
therefore value of X is 0 OR 5 root 3