Question

For any positive integer n, [(n+8)(n+9)(n+10)] is always divisible by
(a)only 3 (b) only 6 (c)both 3 and 6 (d)none of 3 and 6

Answer 1

Answer:

opt c) both 3 and 6

Step-by-step explanation:

(n+8)(n+9)(n+10) is divisible by ............

for example

substitute 1 in place of n

(1+8)(1+9)(1+10)

9x10x11

990. divisible by 3 and 6

substitute 2 in place of n

(2+8)(2+9)(2+10)

10x11x12

1320. divisible by 3 and 6

substitute 3 in place of n

(3+8)(3+9)(3+10)

11x12x13

1716. divisible by 3 and 6

and so on........

hence, For any positive integer n, [(n+8)(n+9)(n+10)] is always divisible by 3 and 6