For any positive integer n, prove that n^2+ n is even integer
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Step-by-step explanation:
Let n be the positive integer.
So, (n^2 +n) = n(n+1)
Since, sum of n numbers = n(n+1)/2
2x sum of n numbers = n(n+1)
We know that any number multiplied by 2 becomes even
Therefore, n(n+1) is an even number.
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