Question

. For any positive integer n, prove that (n^3 – n) is divisible by 6.
​

Answer 1

Step-by-step explanation:

let us take value of n to be 2

then

$( {n}^{3} - n)$

will be

$( {2}^{3} - 2)$

(8-2)=6

which is divisible by 6