for any positive integer n prove that n cube - n is divisible by 6
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Case 2: Consider n = 2q + 1
Since, n (n – 1) (n + 1) is divisible by 2 and 3. Therefore, as per the divisibility rule of 6, the given number is divisible by six. n3 – n = n (n – 1) (n + 1) is divisible by 6.
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