Question

. For any positive integer n, prove that n3 – n is divisible by 6.

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Answer 1

Step-by-step explanation:

Out of three (n – 1) , n, (n + 1) one must be even so a is divisible by 2. 2. (n – 1) , n, (n + 1) are consecutive integers thus as proved a must be divisible by 3. Thus, n³ – n is divisible by 6 for any positive integer n.

Answer 2

Step-by-step explanation:

Step-by-step explanation:

Out of three (n – 1) , n, (n + 1) one must be even so a is divisible by 2. 2. (n – 1) , n, (n + 1) are consecutive integers thus as proved a must be divisible by 3. Thus, n³ – n is divisible by 6 for any positive integer n.