for any positive integer 'n' prove that n³ - n is divisible by 6 (or) show that the product of any three consecutive positive integer is always divisible by 6
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Since, n (n – 1) (n + 1) is divisible by 2 and 3. Therefore, as per the divisibility rule of 6, the given number is divisible by six. n3 – n = n (n – 1) (n + 1) is divisible by 6.
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