Question

for any positive integer n, prove that no-n is divisible by 6.​

Answer 1

$\huge\boxed{\underline\underline{\mathcal{\red{A} \green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}$

For any positive integer 'n', (n³ -n) is divisible by 6. Whenever a number is divided by 3, the remainder obtained is either 0 or 1 or 2. ∴ n = 3p or 3p + 1 or 3p + 2, where p is some integer.