for any positive integer n, prove that no-n is divisible by 6.
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For any positive integer 'n', (n³ -n) is divisible by 6. Whenever a number is divided by 3, the remainder obtained is either 0 or 1 or 2. ∴ n = 3p or 3p + 1 or 3p + 2, where p is some integer.
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