Question

For any positive integer n, prove that (nº-n) is divisible by 6.
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Answer 1

Step-by-step explanation:

Therefore,For any positive integer 'n', (n³ -n) is divisible by 6. Whenever a number is divided by 3, the remainder obtained is either 0 or 1 or 2. ... If n = 2q, then n is divisible by 2. If n = 2q + 1, then n – 1 = 2q + 1 – 1 = 2q is divisible by 2 and n + 1 = 2q + 1 + 1 = 2q + 2 = 2 (q + 1) is divisible by 2