Question

For any quadrilateral ABCD, prove that AB+ BC+ CA + DA > AC+BD 

Please help as fast as possible​

Answer 1

Answer:

ANSWER

ABCD is a quadrilateral and AC, and BD are the diagonals.

Sum of the two sides of a triangle is greater than the third side.

So, considering the triangle ABC, BCD, CAD and BAD, we get

AB + BC > AC

CD + AD > AC

AB + AD > BD

BC + CD > BD

Adding all the above equations,

2(AB + BC + CA + AD) > 2(AC + BD)

⇒ 2(AB + BC + CA + AD) > 2(AC + BD)

⇒ (AB + BC + CA + AD) > (AC + BD)

HENCE, PROVED

Answer 2

Answer:

Hey Here Is your Answer

Hope This Helps ☺️☠️