Question

For any real number a, show that the
area of triangle ABC with vertices A (5. a).
B (2, 5) and C (2, 3) is 3.

Answer 1

Answer:

Area of a triangle with vertices (x1,y1) ; (x2,y2)  and (x3,y3)  is ∣∣∣∣∣2x1(y2−y3)+x2(y3−y1)+x3(y1−y2)∣∣∣∣∣

Hence, substituting the points (x1,y1)=(−5,−1) ; (x2,y2)=(3,−5)  and (x3,y3)=(5,2) in the area formula, we get

Area of triangle ABC  =∣∣∣∣∣2(−5)(−5−2)+(3)(2+1)+5(−1+5

Answer 2

Answer:

Here is your answer.

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