For any real number x, let [x] denote the largest integer less than or equal to x. Let f be a real valued function defined on the interval [–
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The question is incomplete here is the complete question:
For any real number x, let [x] denote the largest integer less than or equal to x. Let f be a real valued function defined to the interval [−10,10] by
f(x)={x−[x]1+[x]−xif [x] is oddif [x] is even
Then the value of π210∫−1010f(x)cosπx dx is
Answer:
f(x)={{x}1−{x}2n−1≤x<2n2n≤x<2n+1
f(x) is a periodic function with period = 2
f(x).cosπx is also periodic with period = 2
π210∫−1010f(x)cos(πx)dx=π2∫02f(x)cos(πx)dx=π2∫01((1−{x})+{−x})cos(πx)dx
2π2∫01(−xcosπx)dx = − 2π2[xsinπxπ+cosπxπ2]10=−2π2(−2π2)=4
If there is any confusion please leave a comment below.
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