Question

For any real number x, x² ≥ 0.SState whether the given statement are true or false. Give reasons for your answer.

Answer 1

the statement is true.

square of a real number cannot be negative as square root of a real number is also a real number(not a complex number). but when x=0 then x²=0.

Answer 2

Answer:

The given statement for any real number x, x² ≥ 0 is true

Step-by-step explanation:

Suppose x is a real number.

Then x may be either positive, negative or 0

case 1 : when x = 0, x² = 0

case 2: when x < 0, (-x)(-x) = x²,

            therefore x² > 0

case 3: when x > 0, x² > 0

The square of every real number is always greater than or equal to zero, that is ∀ x ∈ R, x² ≥ 0