Question

For any set a and b prove that (a-b) union (b-a)=(a union b)-(a intersection b)​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

to prove: (a-b) union (b-a)=(a union b)-(a intersection b)

proof :-

LHS;

see, we know that, (a-b) means the objects in 'a' - objects common in 'a' and 'b'

and, (b-a) means the objects in 'b' - objects common in 'a' and 'b'

...... so the union of these two (in the image) means taking all objects from both cases

RHS;

we know that, (a union b) means choosing all objects in 'a and 'b'

and, (a intersection b) means selecting common objects from 'a' and 'b'

......so subtraction of both cases means object present in 1st case of rhs - objects common in both cases of rhs (in the image)

So,  hence proved​