For any sets A and B show that
i) (A∩B)∪(A-B)=A
ii) A∪(B-A)=A∪B
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Step-by-step explanation:
ANSWER ::
Proof of (A∩B)∪(A-B)=A ::
(A∩B)∪(A-B)
= ( A ∩ B ) ∪ ( A ∩ B' )
= A∩ ( B ∪ B')
= A ∩ U
= A
Proof of A∪(B-A)=A∪B ::
A∪(B-A)
= A∪ (B ∩ A' )
= ( A∪B ) ∩ ( A∪ A')
=( A∪B ) ∩ U
= ( A∪B )
Where U = Universal Set
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