For any three positive real numbers a, b and c, 9(25a² + b²) + 25(c² – 3ac) = 15b(3a + c). Then:(a) a, b and c are in G.P.(b) b, c and a are in G.P.(c) b, c and a are in A.P.(d) a, b and c are in A.P.
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option(c)
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