For any three sets A, B and C, show that if A ⊂ B then C – B ⊂ C – A.
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Answer:
Hence proved that C-BC−B is the subset of C-AC−A if A is a subset of B.
Solution:
Let us consider the sets of A, B and C as follows
A = {a, b, c}
B = {a, b, c, d, e}
C = {a, b, c, d, e, f, g}
So here, we are taking A as the subset of B and B is the subset of C.
∴ C-BC−B = {f,g}
∴ C- AC−A = {d,e,f,g}
Here, we can find that the C-BC−B contains the values of C-AC−A and C-AC−A has more values other than C-BC−B
Hence we can prove that (C-B)(C−B) is the subset of (C-A)(C−A) if A is the subset of B.
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