Question

for any triangle ABC, find the value of cos(A+B+C)/2​

Answer 1

Answer:

cos 90  =  0

Step-by-step explanation:

for any triangle ABC,

sum of angles -  A + B + C = 180

so cos (A + B + C) / 2  =  180/2  =   90°

cos 90° =  0

Answer 2

Answer:

The value of cos(A+B+C)/2​ is 0.

Step-by-step explanation:

Given,

ABC is a triangle.

To find,

The value of cos(A + B + C)/2

Calculation,

We know that in a triangle the sum of all the angles is equal to 180°, which is known as the angle sum property of the triangle.

Here the three angles of the triangle are:

A, B, and C

So, A + B + C = 180°

And (A + B + C)/2 = 180°/2 = 90°

Hence, cos(A + B + C)/2 = cos(90°) = 0

Therefore, the value of cos(A+B+C)/2​ is 0.

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