for any triangle ABC prove that
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Hey !!!
from LHS
a + b / c
we know sine formula
a/sin2A = 2E
•°• a = 2RsinA
b = 2R sinB
c = 2R sinC
therefore , 2RsinA + 2RsinB / 2R sinC
=> sinA + sinB / sinC
we know,
sinA + sinB = 2sin (A + B)/2 *cos ( A -B) /2
And sinC = 2sinc/2 cosC/2
since,
= 2sin(A + B) /2 cos ( A - B)/2
_________________________
2sinC/2 cosC /2
=2sin ( 90° - C/2) cos ( A- B)/2 ______________________
2sinC/2 cosC/2
=> cosC /2 cos ( A - B) /2
_____________________
2sinC/2 cosC/2
=> cos ( A - B )/2
_______________
cosC/2
LHS = RHS prooved ♻
__________________________
Hope it helps you !!!
@Rajukumar111
from LHS
a + b / c
we know sine formula
a/sin2A = 2E
•°• a = 2RsinA
b = 2R sinB
c = 2R sinC
therefore , 2RsinA + 2RsinB / 2R sinC
=> sinA + sinB / sinC
we know,
sinA + sinB = 2sin (A + B)/2 *cos ( A -B) /2
And sinC = 2sinc/2 cosC/2
since,
= 2sin(A + B) /2 cos ( A - B)/2
_________________________
2sinC/2 cosC /2
=2sin ( 90° - C/2) cos ( A- B)/2 ______________________
2sinC/2 cosC/2
=> cosC /2 cos ( A - B) /2
_____________________
2sinC/2 cosC/2
=> cos ( A - B )/2
_______________
cosC/2
LHS = RHS prooved ♻
__________________________
Hope it helps you !!!
@Rajukumar111
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