Question

For any two complex numbers z and w, prove that |z+w|≤|z|+|w|.​

Answer 1

I will write conjugate of z and w as Z and W ok ?

|z+w|^2 = (z+w)(Z+W)

= (zZ + wW + 2(zW+ Zw)

= |z|^2 + |w|^2 + 2 (zW+ Zw)

therefore

Step-by-step explanation:

Answer 2

Answer:

thanks for helping me late night