Math, asked by mdshahabuddin2508200, 6 months ago

For any two events A and
and B prove that,
P(AUB)<P(A) + P(B).
​

Answers

Answered by sojahsfinest
1

Answer:

f A and b are two different events then, P(A U B) = P(A) + P(B) - P(A ∩ B). ... P(A U B) is the probability of the sum of all sample points in A U B. Now P(A) + P(B) is the sum of probabilities of sample points in A and in B.

Step-by-step explanation:

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