For any two natural number p and q we define the operators ^,v as follows p^q=p2+q2,pvq=p2-q2 then the value of (5v2)^25 is
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I don't know the answer is yes I am not sure if you can do it is not clear on what I am a
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1066
Step-by-step explanation:
5^6=5 square - 2 square=21
so, 21 square+ 25 square=1066
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