Math, asked by nischithbhandary67, 1 year ago

For Any two positive integers a,b there exist unique integers q and r such that a=bq+r if B=4then which is not the value of r
A)0 B)1. C)2. D) 3 E) 4
Plzz example with explanation proper reasons also will get best answer

Answers

Answered by HashtagNoName
6

Answer:

(e) 4

Given condition, 0 ≤ r < b

If b = 4,

0 ≤ r < 4

So, r can be

0, or 1, or, 2, or 3.

But, r cannot be 4, as r < 4

So, (e) is the correct answer

Answered by amitnrw
0

Correct option is option E) 4

For Any two positive integers a,b there exist unique integers q and r such that a=bq+r and b = 4 then  4 is not the value of r

Euclid's Division Lemma

a=bq+r

a = dividend

b = divisor

q = quotient

r = remainder

0 ≤ r < b

as b = 4 Hence  0 ≤ r < 4

so r can be 0 , 1 , 2 , 3

Hence in the given options 4 is not a possible value

so Correct option is option E) 4

For Any two positive integers a,b there exist unique integers q and r such that a=bq+r and b = 4 then  4 is not the value of r

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