For Any two positive integers a,b there exist unique integers q and r such that a=bq+r if B=4then which is not the value of r
A)0 B)1. C)2. D) 3 E) 4
Plzz example with explanation proper reasons also will get best answer
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Answered by
6
Answer:
(e) 4
Given condition, 0 ≤ r < b
If b = 4,
0 ≤ r < 4
So, r can be
0, or 1, or, 2, or 3.
But, r cannot be 4, as r < 4
So, (e) is the correct answer
Answered by
0
Correct option is option E) 4
For Any two positive integers a,b there exist unique integers q and r such that a=bq+r and b = 4 then 4 is not the value of r
Euclid's Division Lemma
a=bq+r
a = dividend
b = divisor
q = quotient
r = remainder
0 ≤ r < b
as b = 4 Hence 0 ≤ r < 4
so r can be 0 , 1 , 2 , 3
Hence in the given options 4 is not a possible value
so Correct option is option E) 4
For Any two positive integers a,b there exist unique integers q and r such that a=bq+r and b = 4 then 4 is not the value of r
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