for any two rational numbers a and b it follows that a^3-b^3= (a-b)(a^2+ab+b^2) using this formula find the cube of 1001
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a³ - b³ = ( a - b) ( a² + a b + b² )
(a - b) ( a² + a b + b² )
(a - b) ( a² + a b + b² )a ( a² + a b + b² ) - b ( a² + ab + b² )
(a - b) ( a² + a b + b² )a ( a² + a b + b² ) - b ( a² + ab + b² )a³ + a²b + ab² - a²b -ab² - b³
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