For any two sets A and B, prove that
(iv) A ∪ (B – A) = A ∪ B
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(iv) A ∪ (B – A) = A ∪ B
Consider LHS A ∪ (B – A)
Suppose, x ∈ A ∪ (B – A) ⇒ x ∈ A or x ∈ (B – A)
⇒ x ∈ A or x ∈ B and x ∉ A
⇒ x ∈ B
⇒ x ∈ (A ∪ B) (here, B ⊂ (A ∪ B))
This is true for all x ∈ A ∪ (B – A)
∴ A ∪ (B – A) ⊂ (A ∪ B)…… (1)
Conversely,
Suppose x ∈ (A ∪ B) ⇒ x ∈ A or x ∈ B
⇒ x ∈ A or x ∈ (B – A) (here, B ⊂ (A ∪ B))
⇒ x ∈ A ∪ (B – A)
∴ (A ∪ B) ⊂ A ∪ (B – A)…… (2)
From the equation 1 and 2 we get,
A ∪ (B – A) = A ∪ B
Thus proved
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