for AP 3,9,15,21.............. . find S10
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From given AP
a=3
d=6
n=10
Sn=(n/2)[a+(n-1).d]
==>(10/2)[3+9*6]
==>5*57
==>185
a=3
d=6
n=10
Sn=(n/2)[a+(n-1).d]
==>(10/2)[3+9*6]
==>5*57
==>185
niharika44:
sorry it is also wrong
What's wrong
It's correct
Sn=(n/2)[2a+(n-1).d]==>(10/2)[2*3+(10-1)*6]==>5*[6+54
]==>5*60==>300
Sry above answer is correct
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