For AP, if tp = q and tq = p show that tp + q = 0
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Answer:
Tp=a+(p−1)d=q
Tq=a+(q−1)d=p
solving the above two equations,
(p−q)d=(q−p),d=−1
a=p+q−1
Tp+q=a+(p+q−1)(−1)=a−a=0
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