for ap s16=784 d=6 find a
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(i) S16=784
a=4
$$\begin{lgathered}s16 = \frac{16}{2} (2 \times 4 + (16 - 1)d) \\ 784 = 8(8 + 15d) \\ 98 = 8 + 15d \\ 90 = 15d \\ \huge \bold{16 = d}\end{lgathered}$$
(ii)S12=-78
d=-3
$$\begin{lgathered}s12 = \frac{12}{2} (2a + (12 - 1) - 3) \\ - 78 = 6(2a + 11( - 3) \\ - 13 = 2a - 33 \\ - 13 + 33 = 2a \\ 20 = 2a \\ \huge\bold{a = 10}\end{lgathered
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